Re: why does exit() print its argument?

How about if we overload it a bit. I think anybody who does exit(1) is expecting 1 to be set as the return status whereas someone who does exit('something bad happened') is expecting the string to be shown a-la die(). So let's just check the arg and do the appropriate thing. I would be very surprised if that broke anything. -Rasmus On Sat, 29 Sep 2001, Zeev Suraski wrote: > At 03:10 29-09-01, Jim Winstead wrote: > >On Sat, Sep 29, 2001 at 02:12:51AM +0200, Zeev Suraski wrote: > > > Uhm, I'm not dumb :) Of course it enables you to do that, but that's the > > > wrong place to put it. exit() has, since its introduction, been a > > complete > > > equivalent of die(), and had nothing to do with exit statuses. Putting > > > this code there was wrong (even though who knows, maybe I even did that). > > > >no, sascha did. php3 does the same thing. > > Ok, looks like it's old enough (as old as mid 1999). We should probably > leave it at that and introduce a new shell_exit() function. > > Zeev > > >