Re: why does exit() print its argument?
| From: | (Stig Sæther Bakken) | Date: | Sat, 29 Sep 2001 03:53:38 +0000 |
| Subject: | Re: why does exit() print its argument? | ||
| References: | 1 2 | Groups: | php.dev |
| Request: | Send a blank email to php-dev+get-66815@lists.php.net to get a copy of this message | ||
WTF factor: WTF is shell_exit? Exit to shell? Does it start a shell?
:-)
- Stig
[Zeev Suraski <zeev@zend.com>]
> Is there any good reason not to simply add a new function? It's not
> as if it ever behaved that way. This magic tends to later fire back
> at us.
>
> Zeev
>
> At 03:17 29-09-01, Rasmus Lerdorf wrote:
> >How about if we overload it a bit. I think anybody who does exit(1) is
> >expecting 1 to be set as the return status whereas someone who does
> >exit('something bad happened') is expecting the string to be shown a-la
> >die(). So let's just check the arg and do the appropriate thing. I would
> >be very surprised if that broke anything.
> >
> >-Rasmus
> >
> >On Sat, 29 Sep 2001, Zeev Suraski wrote:
> >
> > > At 03:10 29-09-01, Jim Winstead wrote:
> > > >On Sat, Sep 29, 2001 at 02:12:51AM +0200, Zeev Suraski wrote:
> > > > > Uhm, I'm not dumb :) Of course it enables you to do that, but
> > that's the
> > > > > wrong place to put it. exit() has, since its introduction, been a
> > > > complete
> > > > > equivalent of die(), and had nothing to do with exit statuses. Putting
> > > > > this code there was wrong (even though who knows, maybe I even
> > did that).
> > > >
> > > >no, sascha did. php3 does the same thing.
> > >
> > > Ok, looks like it's old enough (as old as mid 1999). We should probably
> > > leave it at that and introduce a new shell_exit() function.
> > >
> > > Zeev
> > >
> > >
> > >
>
>
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--
Stig Sæther Bakken <ssb@alltheweb.com>
Fast Search & Transfer ASA, Trondheim, Norway