Re: why does exit() print its argument?
| From: | Yasuo Ohgaki | Date: | Sun, 30 Sep 2001 04:31:46 +0000 |
| Subject: | Re: why does exit() print its argument? | ||
| References: | 1 2 3 | Groups: | php.dev |
| Request: | Send a blank email to php-dev+get-66844@lists.php.net to get a copy of this message | ||
Markus Fischer wrote:
-1 for PHP 4.0.x +1 for PHP 4.1 or greater.Usualy I am very much against breaking backwards compatibility, but in this case I think it's the best thing to do... Because: - It's already documented that way - It's the 'expected' behaviour (from other languages, and from the docs) As Rasmus said: It would be surprising if this broke a lot of (or even any) code.+1 Hey, my second vote O_o