Re: why does exit() print its argument?
| From: | Markus Fischer | Date: | Sat, 29 Sep 2001 19:06:11 +0000 |
| Subject: | Re: why does exit() print its argument? | ||
| References: | 1 2 | Groups: | php.dev |
| Request: | Send a blank email to php-dev+get-66834@lists.php.net to get a copy of this message | ||
> Usualy I am very much against breaking backwards compatibility, but in this
> case I think it's the best thing to do... Because:
> - It's already documented that way
> - It's the 'expected' behaviour (from other languages, and from the docs)
>
> As Rasmus said: It would be surprising if this broke a lot of (or even any)
> code.
+1
Hey, my second vote O_o