Re: why does exit() print its argument?
| From: | Jim Winstead | Date: | Sat, 29 Sep 2001 01:10:32 +0000 |
| Subject: | Re: why does exit() print its argument? | ||
| References: | 1 2 3 4 | Groups: | php.dev |
| Request: | Send a blank email to php-dev+get-66810@lists.php.net to get a copy of this message | ||
On Sat, Sep 29, 2001 at 02:12:51AM +0200, Zeev Suraski wrote:
> Uhm, I'm not dumb :) Of course it enables you to do that, but that's the
> wrong place to put it. exit() has, since its introduction, been a complete
> equivalent of die(), and had nothing to do with exit statuses. Putting
> this code there was wrong (even though who knows, maybe I even did that).
no, sascha did. php3 does the same thing.
jim